A truck moves at $36 k m h^{- 1}$ . It increases its velocity to $90 k m h^{- 1}$ in $0.1 m i n u t e$ .

What is the acceleration of the truck?

4.5 m s^{- 2}

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5.5 m s^{- 2}

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2.0 m s^{- 2}

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2.5 m s^{- 2}

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Solution

The correct option is D $2.5 m s^{- 2}$
Given,

Initial velocity of the truck, $u = 36 k m h^{- 1} = 36 \times \frac{5}{18} = 10 m s^{- 1}$

Final velocity of the truck, $v = 90 k m h^{- 1} = 90 \times \frac{5}{18} = 25 m s^{- 1}$

Total time taken, $t = 0.1 minute = 6 s$

We know,
Equation of motion as :
$v = u + a t,$
$\Rightarrow a = \frac{v - a}{t},$
Acceleration $= \frac{15}{6} = 2.5 m s^{- 2}$

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