A truck of mass 500 kg moving at 4 m/s collides with another truck of mass 1500 kg moving in the same direction at 2 m/s. What is their common velocity just after the collision if they move off together?

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Solution

Common velocity just after the collision if they move off together will be:
$v = \frac{(m_{1} \times u_{1}) + (m_{2} + u_{2})}{m_{1} + m_{2}}$
m₁ = 500kg,
u₁ = 4 m/s
m₂ = 1500kg
u₂ = 2 m/s
$v = \frac{(500 + 4) + (1500 \times 2)}{500 + 1500} \Rightarrow v = \frac{2000 + 3000}{2000} \Rightarrow v = \frac{5000}{2000} \Rightarrow v = \frac{5000}{2000} \Rightarrow v = 2.5 m / s$
This is their common velocity after collision.

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A truck of mass 500 kg moving at 4 m/s collides with another truck of mass 1500 kg moving in the same direction at 2 m/s. What is their common velocity just after the collision if they move off together?

Common velocity just after the collision if they move off together will be: v=m1×u1+m2+u2m1+m2 m1 = 500kg, u1 = 4 m/s m2 = 1500kg u2 = 2 m/s v=500+4+1500×2500+1500⇒v=2000+30002000⇒v=50002000⇒v=50002000⇒v=2.5 m/s This is their common velocity after collision.