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Question

A tuning fork (pair) produces 4 beats/sec with another fork of frequency 288 Hz. A little wax is placed on the unknown fork and it then produces 2 beats/sec. The frequency of the unknown fork is


A

286 Hz

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B

292 Hz

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C

294 Hz

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D

288 Hz

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Solution

The correct option is

D

292 Hz

Frequency of the unknown fork = 288 ± 4

= 284 or 292

On placing wax, its frequency decreases

the frequency of the unknown fork = 292 Hz


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