A tuning fork (pair) produces 4 beats/sec with another fork of frequency 288 Hz. A little wax is placed on the unknown fork and it then produces 2 beats/sec. The frequency of the unknown fork is
The correct option is
D
292 Hz
Frequency of the unknown fork = 288 ± 4
= 284 or 292
On placing wax, its frequency decreases
⇒ the frequency of the unknown fork = 292 Hz