A two-phase load draws the following phase current-i1f - Imsin- t-1 i2f - Imcos- t-2 These currents are balanced if -1 is equal to

In two phase, currents are balanced if phase difference is 90^0 i_1(t) = I_m sin(ω t ϕ _1) nbsp; i_2(t) = I_m sin(ω t ϕ _2 + 90^o) nbsp; Phase differ ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Other

Circuit Theory

Three phase circuits

A two-phase l...

Question

A two-phase load draws the following phase current:

$i_{1} (f) = I_{m} s i n (ω t - ϕ_{1})$

$i_{2} (f) = I_{m} c o s (ω t - ϕ_{2})$

These currents are balanced if $ϕ_{1}$ is equal to

ϕ_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

ϕ_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(\frac{π}{2} - ϕ_{2})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(\frac{π}{2} + ϕ_{2})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $ϕ_{2}$
In two phase, currents are balanced if phase difference is $90^{0}$

$i_{1} (t) = I_{m} s i n (ω t - ϕ_{1})$

$i_{2} (t) = I_{m} s i n (ω t - ϕ_{2} + 90^{o})$

Phase difference is $90^{o}$ ,

$ω t - ϕ_{2} + 90^{o} - (ω t - ϕ_{1}) = 90^{o}$

$ω t - ϕ_{2} + 90^{o} - ω t + ϕ_{1} = 90^{o}$

$ϕ_{1} - ϕ_{2} = 0$

$ϕ_{1}$ = $ϕ_{2}$

Suggest Corrections

A two-phase load draws the following phase current: i1(f)=Imsin(ωt−ϕ1) i2(f)=Imcos(ωt−ϕ2) These currents are balanced if ϕ1 is equal to

The correct option is B ϕ2In two phase, currents are balanced if phase difference is 900 i1(t)=Imsin(ωt−ϕ1) i2(t)=Imsin(ωt−ϕ2+90o) Phase difference is 90o, ωt−ϕ2+90o−(ωt−ϕ1)=90o ωt−ϕ2+90o−ωt+ϕ1=90o ϕ1−ϕ2=0 ϕ1 = ϕ2

A two-phase load draws the following phase current:

$i_{1} (f) = I_{m} s i n (ω t - ϕ_{1})$

$i_{2} (f) = I_{m} c o s (ω t - ϕ_{2})$

These currents are balanced if $ϕ_{1}$ is equal to