A uniform force of 3 - N acts on a particle of mass 2 kg - Hence- the particle is displaced from position 2 -k- m to position 4 -3 -k- m The work done by the force on the particle is-A- 6 JB- 9 JC- 13 JD- 15 J

The correct option is B 9JF⃗=(3î+ĵ)N r⃗_⃗1⃗=2î+k̂ r⃗_⃗2⃗=4î+3ĵ k̂ Δr⃗_⃗1⃗=r⃗_⃗2⃗ r⃗_⃗1⃗ 4î+3ĵ k̂ 2î k̂ Δr⃗=2î+3ĵ 2k̂ W=F⃗.r⃗ W=(3î+ĵ)(2î+3ĵ 2k̂) W=6+3= ...

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Byju's Answer

Standard XII

Physics

Acceleration in 2D

A uniform for...

Question

A uniform force of $(3^i +^j) N$ acts on a particle of mass 2kg. Hence, the particle is displaced from position $(2^i +^k) m$ to position $(4^i + 3^j -^k) m$ . The work done by the force on the particle is:

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Solution

The correct option is A 9J
$\to F = (3^i +^j) N_{1} = 2^i +^k_{2} = 4^i + 3^j -^k Δ_{1} =_{2} -_{1} 4^i + 3^j -^k - 2^i -^k Δ \to r = 2^i + 3^j - 2^k W = \to F . \to r W = (3^i +^j) (2^i + 3^j - 2^k) W = 6 + 3 = 9 J$

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A uniform force of (3^i+^j)N acts on a particle of mass 2kg. Hence, the particle is displaced from position (2^i+^k)m to position (4^i+3^j−^k)m. The work done by the force on the particle is:

The correct option is A 9J→F=(3^i+^j)N→r1=2^i+^k →r2=4^i+3^j−^kΔ→r1=→r2−→r14^i+3^j−^k−2^i−^kΔ→r=2^i+3^j−2^kW=→F.→rW=(3^i+^j)(2^i+3^j−2^k)W=6+3=9J

A uniform force of $(3^i +^j) N$ acts on a particle of mass 2kg. Hence, the particle is displaced from position $(2^i +^k) m$ to position $(4^i + 3^j -^k) m$ . The work done by the force on the particle is:

The correct option is A 9J
$\to F = (3^i +^j) N_{1} = 2^i +^k_{2} = 4^i + 3^j -^k Δ_{1} =_{2} -_{1} 4^i + 3^j -^k - 2^i -^k Δ \to r = 2^i + 3^j - 2^k W = \to F . \to r W = (3^i +^j) (2^i + 3^j - 2^k) W = 6 + 3 = 9 J$