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Question

A uniform force of (3^i+^j)N newton acts on a particle of mass 2 kg. Hence the particle is displaced from position (2^i+^k) meter to position (4^i+3^j^k) meter. The work done by the force on the particle is:-

A
15 J
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B
9 J
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C
6 J
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D
13 J
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Solution

The correct option is B 9 J
Given F=3^i+^j, Position r1=2^i+^k and r2=4^i+3^j^k
Displacement, d=r2r1=2^i+3^j2^k
Work done =F.d=(3^i+^j).(2^i+ 3^j2^k)=6+3=9J

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