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Question

A uniform force of (3^i+^j) newton acts on a particle of mass 2kg Hence the particle is displaced from position (2^i+^k) metre to position (4^i+3^j^k)metre . the work done by the force on the particle is

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Solution

Given that
a uniform force ,F=3^i+^j
Mass ,m=2kg
Initial position of particle , r1=2^i+^k m

Final position of particle, r2=4^i+3^j^k m

Net Displacement of particle , Δr=r2r1=2^i+3^j2^k m

Work done by the force on the particle , W=FΔr=6+3=9J

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