A velocity-time graph for a moving object is shown below. What would be the total displacement during time $t = 0$ to $t = 6 s$ ?

10

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20

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15

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0.0

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Solution

The correct option is A $10$ m
Total displacement during $0 t o t = 65$ is equal to area under the graph $= A_{1} + A_{2} + A_{3}$
Displacement $= (5 \times 2) + (\frac{1}{2} \times 2 \times 5) + \frac{1}{2} \times (- 5) \times 2$
$= 10 + 5 - 5 = 10 m$

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