A verandah 1.25 m is constructed all along outside of a room 7.5 m long and 5 m wide. Find
(i) the area of the verandah.
(ii) the cost of cementing the floor of the verandah at the rate of Rs.15 per $m^{2}$ .

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Solution

Area of the room is given by $7.5 m \times 5 m$ = $37.5 m^{2}$
Area of the verandah with room is given by $(7.5 + 1.25 + 1.25) m \times (5 + 1.25 + 1.25) m = 10 m \times 7.5 m = 75 m^{2}$
$∴$ The area of the verandah = $75 m^{2}$ - $37.5 m^{2}$ = $37.5 m^{2}$
Cost of cementing the floor of the verandah = $R s .15 / m^{2}$
Total cost of cementing the floor of the verandah = $37.5 \times 15 = R s 562.5$

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A verandah of width $2.25 m$ is constructed all along outside a room which is $5.5 m$ long and $4 m$ wide. Find:

(i) the area of the verandah

(ii) the cost of cementing the floor of the verandah at the rate of $R s . 200$ per $m^{2}$ .

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