A vessel is half filled with a liquid at 0 $^{0}$ C. When then vessel is heated to 100 $^{0}$ C the liquid occupies 3/4 volume of the vessel. Coefficient of apparent expansion of the liquid is :

0.5 /^{o}

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0.05 /^{o}

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0.005 /^{o}

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0.0005 /^{o}

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Solution

The correct option is D $0.005 /^{o}$ C
$γ_{a} = \frac{V_{2} - V_{1}}{V_{1} \times (t_{2} - t_{1})}$ ....(1)
Given,
$V_{1} = \frac{1}{2}$
$V_{2} = \frac{3}{4}$
$t_{2} - t_{1} = 100 - 0 = 100$
Putting the values in (1)
$γ_{a} = \frac{(\frac{3}{4} - \frac{1}{2})}{\frac{1}{2} \times 100} = 0.005$

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A vessel is half filled with a liquid at 00C. When then vessel is heated to 1000C the liquid occupies 3/4 volume of the vessel. Coefficient of apparent expansion of the liquid is :

The correct option is D 0.005/oCγa=V2−V1V1×(t2−t1) ....(1)Given,V1=12V2=34t2−t1=100−0=100Putting the values in (1)γa=(34−12)12×100=0.005

A vessel is half filled with a liquid at 0 $^{0}$ C. When then vessel is heated to 100 $^{0}$ C the liquid occupies 3/4 volume of the vessel. Coefficient of apparent expansion of the liquid is :

The correct option is D $0.005 /^{o}$ C
$γ_{a} = \frac{V_{2} - V_{1}}{V_{1} \times (t_{2} - t_{1})}$ ....(1)
Given,
$V_{1} = \frac{1}{2}$
$V_{2} = \frac{3}{4}$
$t_{2} - t_{1} = 100 - 0 = 100$
Putting the values in (1)
$γ_{a} = \frac{(\frac{3}{4} - \frac{1}{2})}{\frac{1}{2} \times 100} = 0.005$