A vessel of $120 m L$ capacity contain amount of gas at $35^{o} C$ and $1.2$ bar pressure The gas is transferred to another vessel of volume $180 m L$ at $35^{o} C$ . What would be its pressure?

Open in App

Solution

The temperature and the amount of gas is constant. Hence, pressure is calculated from Boyle's law.
$P^{'} = \frac{P V}{V^{'}} = \frac{1.2 \times 120}{180} = 0.8 b a r$

Suggest Corrections

Similar questions

A vessel of 120 mL capacity contains a certain amount of gas at $35^{\circ} C$ and 1.2 bar pressure.
The gas is transferred to another vessel of volume 180 mL at $35^{\circ} C$ . What would be its pressure?

A vessel of capacity 600cm³ contains Hydrogen gas at a pressure of 304 cm of Hg. What will be the pressure of Hydrogen gas, when the vessel is connected to another vessel of the volume of 300cm³ capacity.

Q. A vessel of

120 c m^{3}

contains a certain mass of a gas at

20^{\circ} C

and

750 t o r r

pressure. The gas was transferred to a vessel of volume

180 c m^{3}

. Calculate the pressure of he gas at the same temperature.

Q. A vessel contains

1.6

g of dioxygen at STP (

273.15

1

atm pressure). The gas is now transferred to another vessel at constant temperature, where pressure becomes half of the original pressure. The volume of the new vessel is:

Q. A vessel has

N_{2}

gas and water vapours at a total pressure of 1 atm. The partial pressure of water vapours is 0.3 atm. The contents of this vessel are transferred to another vessel having one-third of the capacity of original volume, completely at the same temperature the total pressure of this system in the new vessel is

Join BYJU'S Learning Program

A vessel of 120 mL capacity contain amount of gas at 35oC and 1.2 bar pressure The gas is transferred to another vessel of volume 180 mL at 35oC. What would be its pressure?

The temperature and the amount of gas is constant. Hence, pressure is calculated from Boyle's law.P′=PVV′=1.2×120180=0.8bar

A vessel of $120 m L$ capacity contain amount of gas at $35^{o} C$ and $1.2$ bar pressure The gas is transferred to another vessel of volume $180 m L$ at $35^{o} C$ . What would be its pressure?

The temperature and the amount of gas is constant. Hence, pressure is calculated from Boyle's law.
$P^{'} = \frac{P V}{V^{'}} = \frac{1.2 \times 120}{180} = 0.8 b a r$