Question

A vessel of 120 mL capacity contains a certain amount of gas at ${35}^{\circ }C$ and 1.2 bar pressure.
The gas is transferred to another vessel of volume 180 mL at ${35}^{\circ }C$. What would be its pressure?

Answer 1

Given,
Initial pressure, $p_1=1.2bar$
Initial volume, $V_1=120mL$
Final volume, $V_2=180mL$
Since the temperature remains constant, the final pressure $\left(p_2\right)$ can be calculated using
Boyle's law.
According to Boyle's law,
$p_1=p_2{v}_2{P}_2=\frac{p_1{V}_1}{V_2}=\frac{1.2\times 120}{180}bar=0.8bar$
Therefore, the pressure would be 0.8 bar.