A village, having a population of $4000$ , requires a $150$ litre water per head per day. It has a tank measuring $20 m \times 25 m \times 15 m$ . For how many days will the water of this tank last?

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Solution

Tank measurement $20 m \times 25 m \times 15 m .$
Volume of water in tank $= 20 \times 25 \times 15$
$= 7500 m^{3}$ $= 7500000 L$ .......... $[1 m^{3} = 1000 L]$

Water required $= 4000 \times 150 L$
$= 600000 L$
No of days $= \frac{7500000}{600000} = 12.5 d a y s .$

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A village having a population of 4000 requires 150 litres of water per head per day. It has a tank measuring $20 m \times 15 m \times 6 m .$ For how many days will the water of this tank last?

Question 6
A village, having a population of 4000, requires 150 litres of water per head per day.

It has a tank measuring $20 m \times 15 m \times 6 m$ . For how many days will the water of this tank last?

Q. A village, having a population of 4000, requires 150 litres water per head per day. It has a tank which is 20 m long, 15 m broad and 6 m high. For how many days will the water of this tank last?

Q. A village having a population of

4000

, requires

150

litres water per head per day. It has a tank measuring

20 m, 15 m, 6 m

. How many days for the water is sufficient enough once the tank is made full

A village, having a population of 4000, requires 150 litres of water per head per day.

It has a tank measuring $20 m \times 15 m \times 6 m$ . For how many days will the water of this tank last?

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A village, having a population of 4000, requires a 150 litre water per head per day. It has a tank measuring 20m×25m×15m. For how many days will the water of this tank last?

Tank measurement 20m×25m×15m.Volume of water in tank =20×25×15 =7500m3=7500000L.......... [1m3=1000L]Water required =4000×150L =600000LNo of days=7500000600000=12.5days.

A village, having a population of $4000$ , requires a $150$ litre water per head per day. It has a tank measuring $20 m \times 25 m \times 15 m$ . For how many days will the water of this tank last?

Tank measurement $20 m \times 25 m \times 15 m .$
Volume of water in tank $= 20 \times 25 \times 15$
$= 7500 m^{3}$ $= 7500000 L$ .......... $[1 m^{3} = 1000 L]$

Water required $= 4000 \times 150 L$
$= 600000 L$
No of days $= \frac{7500000}{600000} = 12.5 d a y s .$