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Question

A wall of dimensions 2.00m by 3.50m has a single-pane window of dimensions 0.75m by 1.20m If the inside temperature is 20 and the outside temperature is 10, effective thermal resistance of the opaque wall and window are 2.10KW1 and 0.21KW1 respectively. The heat flow through the entire wall will be.

A
215W
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B
205W
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C
175W
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D
110W
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Solution

The correct option is A 215W
The wall and the window are in a parallel arrangement, so net heat flow is the sum of the heat flow through the wall and the window.
The temperature difference,
THTC=30K
Area of window,
A1=(0.75)(1.20)=0.90
Heat flow through window pane,
(dQdt)1=THTCR1

=(0.90)300.21

=128.6W
The area of the wall,
Heat flow through the wall,
(dQdt)2=THTCR2

=(6.10)(30)(2.10)

=87W
Net heat flow, dQdt=128.6+87
=215.6W

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