Question

A wire carrying a current of $5A$is placed perpendicular to a magnetic induction of$2T$. The force on each $centimetre$of the wire is

• A. $0.1N$
• B. $100N$
• C. 10 N
• D. 1 N

Answer 1

The correct option is A

$0.1N$

Step 1. Given data

Current is,$I=5cm$

Length is, $L=1cm=0.01m$

Magnetic field, $B=2T$

The angle between the magnetic field and the conductor is, $\theta ={90}^o$.

Step 2. Force formula

$F=lLBSin\theta$

Where, $L$ is length, $I$ is current, $B$ is a magnetic field, $\theta$ is the angle.

Step 3. Finding magnetic force

Substitute all values in force formula,

$F=0.01m\times 5A\times 2T\times Sin{90}^o$

After solving this we get,

$F=0.1N$.

Therefore, the force on each centimeter of the wire is $0.1N$.

Hence, the option $A$ is correct.