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Law of Floatation

A wooden cube...

Question

A wooden cube of side $10 c m$ has mass $700 g$ . What part of it remains above the water surface while floating vertically on the water surface?

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Solution

volume=10x10x10cc=1000cc
density=mass/volume
density of water=1gm/cc
so, 700 cc of cube is inside the water
volume of cube outside the water=1000-700=300 ${c m}^{3}$

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