The correct option is C O.N. of A decreases by +5 and that of C increases by +1
AB−4+C+2→C+3+A+2
From the above equation and the oxidation number of, B we can calculate the O.N of A as follows.
x + 4(−2) = −1
x = +7
The oxidation number of A in the L.H.S of the equation is +7 and in the R.H.S it becomes +2.
Therefore there is a decrease in the oxidation satate of A by +5
Similarly the O.N of C in the L.H.S is +2 and in the R.H.S is +3.
Therefore there is an increase in th O.N of C by +1