Question

ABCD is a rectangle with dimensions 24 m by 16 m. AFD is a triangle such that EF is perpendicular AD and EF = 10 m. Calculate the area of the shaded portion.

Answer 1

7. Area of triangle AFE = $\frac{1}{2}\times 16\times 10=80m^2$
Area of the rectangle = $24\times 16=384m^2$
Area of the shaded portion = 384 - 80 = 304 $m^2$