Question

According to Charle's law, the lowest possible temperature is (in ${}^{o}C$):

Answer 1

According to charle's law,

$V=V_0[1+\frac{t}{273}]$

For $t=-273℃$

$V=V_0[1+\frac{(-273)}{273}]$

$\Rightarrow V=V_0[1-\frac{273}{273}]$

$\Rightarrow V=0$

The volume of any gas at $-273℃$ is zero. Below this temperature, the volume will be negative which is not possible.

Hence according to Charle's law, the lowest possible temperature is $-273℃$.

Therefore, the required answer is $-273℃$.