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Byju's Answer

Standard XII

Chemistry

Dalton's Law of Partial Pressures

According to ...

Question

According to Graham's law, at a given temperature, the ratio of the rates of diffusion $r_{A} / r_{B}$ of gases $A$ and $B$ is given by :
(Here, $p$ and $M$ are pressure and molecular weights of gases $A$ and $B$ , respectively.)

[\frac{P_{A}}{P_{B}}] {[\frac{M_{A}}{M_{B}}]}^{1 / 2}

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[\frac{M_{A}}{M_{B}}] {[\frac{P_{A}}{P_{B}}]}^{1 / 2}

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[\frac{P_{A}}{P_{B}}] {[\frac{M_{B}}{M_{A}}]}^{1 / 2}

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[\frac{M_{A}}{M_{B}}] {[\frac{P_{B}}{P_{A}}]}^{1 / 2}

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Solution

The correct option is B $[\frac{P_{A}}{P_{B}}] {[\frac{M_{B}}{M_{A}}]}^{1 / 2}$
Rate of diffusion is directly proportional to the pressure and inversely propotional to the molar mass of the gas. Hence, $\frac{r_{A}}{r_{B}} = \frac{P_{A}}{P_{B}} {(\frac{M_{B}}{M_{A}})}^{1 / 2}$

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According to Graham's law, at a given temperature, the ratio of the rates of diffusion rA/rB of gases A and B is given by :(Here, p and M are pressure and molecular weights of gases A and B, respectively.)

The correct option is B [PAPB][MBMA]1/2Rate of diffusion is directly proportional to the pressure and inversely propotional to the molar mass of the gas. Hence, rArB=PAPB(MBMA)1/2

According to Graham's law, at a given temperature, the ratio of the rates of diffusion $r_{A} / r_{B}$ of gases $A$ and $B$ is given by :
(Here, $p$ and $M$ are pressure and molecular weights of gases $A$ and $B$ , respectively.)

The correct option is B $[\frac{P_{A}}{P_{B}}] {[\frac{M_{B}}{M_{A}}]}^{1 / 2}$
Rate of diffusion is directly proportional to the pressure and inversely propotional to the molar mass of the gas. Hence, $\frac{r_{A}}{r_{B}} = \frac{P_{A}}{P_{B}} {(\frac{M_{B}}{M_{A}})}^{1 / 2}$