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Question

According to Graham's law, at a given temperature, the ratio of the rates of diffusion rA/rB of gases A and B is given by :
(Here, p and M are pressure and molecular weights of gases A and B, respectively.)

A
[PAPB][MAMB]1/2
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B
[MAMB][PAPB]1/2
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C
[PAPB][MBMA]1/2
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D
[MAMB][PBPA]1/2
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Solution

The correct option is B [PAPB][MBMA]1/2
Rate of diffusion is directly proportional to the pressure and inversely propotional to the molar mass of the gas. Hence, rArB=PAPB(MBMA)1/2

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