According to molecular orbital theory, which of the following will not exist?

H_{2}^{+}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B e_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

B_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $B e_{2}$
According to the molecular orbital theory elements which have bond order negative or $0$ will not exist.

Formula to calculate bond order $= \frac{N u m b e r o f e l e c t r o n s i n B M O - N u m b e r o f e l e c t r o n s i n A B M O}{2}$

where, $B M O =$ Bonding molecular orbital
$A B M O =$ Antibonding molecular orbital

Molecular electronic configuation of $B e_{2} = σ 1 s^{2} σ^{} 1 s^{2} σ 2 s^{2} σ^{} 2 s^{2}$

$B e_{2}$ has $4$ electrons in $B M O$ and $4$ in $A B M O$ so the bond order will come $0$ .

So, the correct option is $[B] .$

Suggest Corrections

Similar questions

B e_{2}

C_{2}

Join BYJU'S Learning Program