CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Weight and Mass

Actual weight...

Question

Actual weight of a man is 600N and in a lift the reading of the weighing machine is 900N, the acceleration of the lift is? (acceleration due to gravity, $(g = 10 m s^{- 2})$

A

\frac{g}{2}

in upward direction

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

B

g

in upward direction

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

\frac{g}{2}

in downward direction

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

g

in downward direction

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $\frac{g}{2}$ in upward direction
Apparent weight of the man is greater than his actual weight so lift is going upward.
Mass = Actual weight / g = 600 /10 = 60 kg
Apparent weight , $W = m (g + a)$
$900 = 60 (10 + a)$
$a = 5 m s^{- 2}$
$a = \frac{g}{2} m s^{- 2}$

Suggest Corrections

thumbs-up

0

Similar questions

Q. A man stands on a weighing machine kept inside a lift. Initially the lift is ascending with the acceleration 'a' due to which the reading is W. Now the lift descends with the same acceleration and reading is 10% of initial. The acceleration of the lift is:

Q. A man weighing 65 kgf is in a lift that is ascending with a uniform acceleration that is equal to the acceleration due to gravity. His apparent weight in the lift will be

Q. A man is standing on a weighing machine placed in a lift. When stationary his weight is recorded as 40 kg. If the lift is accelerated upwards with an acceleration of

2 {m/s}^{2}

, then the weight recorded in the machine will be

(g = 10 m/s)^{2}

Q. A Woman weighing 50 kg stands on a weighting machine placed in a lift. What will be the reading of the machine, When the lift is (i) moving upwards with a uniform velocity of

5 m s^{- 1}

and (ii) moving downwards with a uniform acceleration of

1 m s^{- 2} ?

[T a k e

g = 10 m s^{- 2}] .

Q. A block of mass

m

is placed on a weighing machine and it is also attached to a spring balance. The whole system is placed in a lift as shown in figure. Lift is moving with constant acceleration

10 m / s^{2}

in upward direction. The reading of the weighing machine is

500 N

and the reading of spring balance is

300 N

. Find the actual mass of the block in kg. Take

g = 10 m / s^{2}

.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Weight and Mass

PHYSICS

Watch in App

explore_more_icon

Explore more

Weight and Mass

Standard IX Physics

Join BYJU'S Learning Program

CrossIcon