Actual weight of a man is 600N and in a lift the reading of the weighing machine is 900N, the acceleration of the lift is? (acceleration due to gravity, (g=10ms−2)
A
g2 in upward direction
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B
g in upward direction
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C
g2 in downward direction
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D
g in downward direction
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Solution
The correct option is Ag2 in upward direction Apparent weight of the man is greater than his actual weight so lift is going upward.
Mass = Actual weight / g = 600 /10 = 60 kg
Apparent weight ,W=m(g+a) 900=60(10+a) a=5ms−2 a=g2ms−2