Add and express in the form of a complex number $a + b i$
$(2 + 3 i) + (- 4 + 5 i) - \frac{(9 - 3 i)}{3}$

- 4 + 9 i

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- 5 + 9 i

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2 + 9 i

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- 5 + 8 i

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Solution

The correct option is B $- 5 + 9 i$
Adding the given expression as follows:
$(2 + 3 i) + (- 4 + 5 i) - \frac{(9 - 3 i)}{3}$
$= (2 + 3 i) + (- 4 + 5 i) - (3 - i)$
$= 2 + 3 i - 4 + 5 i - 3 + i$
$= - 5 + 9 i$

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Similar questions

(- 2 - 3 i) - (- 9 + 9 i) - (2 + 5 i)

z_{1} = 2 + 3 i

z_{2} = 7 - 9 i

7 + 9 i

- 3 + 7 i

3 + 3 i

z_{1} = 2 + 3 i

z_{2} = 7 - 9 i

40 + 9 i > 12 + 5 i

\sqrt{- 1} = i

40 > 12

9 > 5

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