Question

Ajay as certain amount in his account.He gives half of it to his eldest son and one third of the remaining to his youngest son.What fraction of the original amount is left with him now?

• A. $\frac{1}{3}$
• B. $\frac{2}{3}$
• C. $\frac{3}{4}$
• D. $\frac{1}{6}$

Answer 1

The correct option is A $\frac{1}{3}$

Let the amount Ajay has in his account $=x$.

Amount the eldest son got $=\frac{x}{2}$

Amount youngest son got $=(x-\frac{x}{2})\times \frac{1}{3}=\frac{x}{6}$.

The amount he is left with $x-\frac{x}{2}-\frac{x}{6}=\frac{x}{3}$.

$\Rightarrow$ He is left with $\frac{1}{3}rd$ of his original amount. $\left[A\right]$