Ajeeta starts off from home at 7 a.m. with her father on a scooter that goes at a uniform speed of 30 km/hr. Her father drops her at her school after half an hour. She stays in the school till 1.30 p.m. and takes an autorickshaw to return home. The autorickshaw has a uniform speed of 10 km/hr. Draw the line graph for the given situation and also determine the distance of Ajeets's school from her home.

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Solution

distance of Ajeets's school from her home is given by
speed = $\frac{distance}{time}$
30 = $\frac{distance}{1 / 2}$

distance = 15 km

Distance-Time graph is given by

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distance of Ajeets's school from her home is given by speed = distancetime 30 = distance1/2 distance = 15 km Distance-Time graph is given by

distance of Ajeets's school from her home is given by
speed = $\frac{distance}{time}$
30 = $\frac{distance}{1 / 2}$

distance = 15 km

Distance-Time graph is given by