Question

Alcohol is pursed through a pipe of 10 cm diameter at 2 m/sec flow velocity the volume flow rate $\left(in{m}^3/sec\right)$ is

• A. 0.02
• B. 0.0157
• C. 0.0257
• D. 0.01

Answer 1

The correct option is B 0.0157

A pipe of 10 cm diameter has a cross-section area of
$A=\frac{\pi D^2}{4}=\frac{\pi \times ({10}^{-1}{)}^2}{4}=7.85\times {10}^{-3}\left(m^2\right)$

The flow rate is
$Q=Av=7.85\times {10}^{-3}\times 2$

$Q=0.0157m^3/sec$