Aluminum chloride exists as a dimer $A l_{2} C l_{6}$ in solid state as well as in solution of non-polar solvents such as $C_{6} H_{6}$ . When dissolved in acidified aqueous solution, it gives:

A l_{2} O_{3} + 6 H C l

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[A l (H_{2} O)_{6}]^{3 +} + 3 C l^{-}

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H_{3} [A l (O H)_{6}] + 6 H C l

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A l^{3 +} + 3 C l^{-}

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Solution

The correct option is B $[A l (H_{2} O)_{6}]^{3 +} + 3 C l^{-}$
$A l_{2} C l_{6}$ when dissolved in acidified aqueous solution gives:
$A l_{2} C l_{6} + 12 H_{2} O \to 2 [A l (H_{2} O)_{6}]^{3 +} + 6 C l^{-}$
Hence, option b is the correct answer.

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Aluminium chloride exists as a dimer ( $A l_{2} C l_{6}$ ) in solid state as well as in solution of non-polar solvents such as $C_{6} H_{6}$ . When dissolved in water it gives:

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in solid state as well as in solution of non-polar solvents like benzene.When dissolved in water, it gives :

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Aluminum chloride exists as a dimer Al2Cl6 in solid state as well as in solution of non-polar solvents such as C6H6. When dissolved in acidified aqueous solution, it gives:

The correct option is B [Al(H2O)6]3++3Cl−Al2Cl6 when dissolved in acidified aqueous solution gives: Al2Cl6+12H2O→2[Al(H2O)6]3++6Cl− Hence, option b is the correct answer.

Aluminum chloride exists as a dimer $A l_{2} C l_{6}$ in solid state as well as in solution of non-polar solvents such as $C_{6} H_{6}$ . When dissolved in acidified aqueous solution, it gives:

The correct option is B $[A l (H_{2} O)_{6}]^{3 +} + 3 C l^{-}$
$A l_{2} C l_{6}$ when dissolved in acidified aqueous solution gives:
$A l_{2} C l_{6} + 12 H_{2} O \to 2 [A l (H_{2} O)_{6}]^{3 +} + 6 C l^{-}$
Hence, option b is the correct answer.