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Standard XI

Chemistry

Mole Concept

Ammonia prepa...

Question

Ammonia prepared by treating ammonium sulphate with calcium hydroxide is completely used by $N i C l_{2} .6 H_{2} O$ to form a stable coordination compound ( $[N i (N H_{3})_{6}] C l_{2}$ ). Assume that both the reactions are $100$ % complete. If $1584$ g of ammonium sulphate and $952$ g of $N i C l_{2} .6 H_{2} O$ are used in the preparation, the combined weight (in grams) of gypsum ( $C a S O_{4} .2 H_{2} O$ ) and the nickel-ammonia coordination compound thus produced is ____.

(The reactions involved are:
$C a (O H)_{2} + (N H_{4})_{2} S O_{4} \to 2 N H_{3} + C a S O_{4} .2 H_{2} O$
$N i C l_{2} .6 H_{2} O + 6 N H_{3} \to [N i (N H_{3})_{6}] C l_{2} + 6 H_{2} O$

Atomic weights in $g m o l^{- 1}$ : $H = 1, N = 14, O = 16, S = 32, C l = 35.5, C a = 40, N i = 59)$

2929 g

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2992 g

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2998 g

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2982 g

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Solution

The correct option is B 2992 g
The reaction for the ammonia formation is $C a (O H)_{2} + (N H_{4})_{2} S O_{4} \to 2 N H_{3} + C a S O_{4} .2 H_{2} O$
$m o l e s : 12 \frac{1584}{132} = 122412$

$∴$ Weight of gypsum $(C a S O_{4} .2 H_{2} O)$ formed = $12 \times 172 = 2064 g$

Again the reaction corresponding to the complex formation is:

$N i C l_{2} .6 H_{2} O + 6 N H_{3} \to [N i (N H_{3})_{6}] C l_{2} + 6 H_{2} O$
$m o l e s : \frac{952}{238} = 424 \frac{24}{6} = 4$

$∴$ Mass of $[N i (N H_{3})_{6}] C l_{2}$ formed = $4 \times 232 = 928 g$
Total Weight = $2064 + 928 = 2992 g$

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Similar questions

Q. Ammonia prepared by treating ammonium sulphate with calcium hydroxide is completely used by

N i C l_{2} .6 H_{2} O

to form a stable coordination compound (

[N i (N H_{3})_{6}] C l_{2}

). Assume that both the reactions are

100

% complete. If

1584

g of ammonium sulphate and

952

g of

N i C l_{2} .6 H_{2} O

are used in the preparation, the combined weight (in grams) of gypsum (

C a S O_{4} .2 H_{2} O

) and the nickel-ammonia coordination compound thus produced is ____.

(The reactions involved are:

C a (O H)_{2} + (N H_{4})_{2} S O_{4} \to 2 N H_{3} + C a S O_{4} .2 H_{2} O

N i C l_{2} .6 H_{2} O + 6 N H_{3} \to [N i (N H_{3})_{6}] C l_{2} + 6 H_{2} O

Atomic weights in

g m o l^{- 1}

H = 1, N = 14, O = 16, S = 32, C l = 35.5, C a = 40, N i = 59)

Q. The ammonia prepared by treating ammonium sulphate with calcium hydroxide is completely used by

N i C l_{2} . 6 H_{2} O

to form a stable coordination compound. Assume that both the reactions are 100% complete. If 1584 g of ammonium sulphate and 952 g of

N i C l_{2} .6 H_{2} O

are used in the preparation, the combined weight (in grams) of gypsum and the nickel-ammonia coordination compound thus produced is .
(Atomic weights in g

m o l^{- 1}

H

= 1,

N

= 14,

O

= 16,

S

= 32,

C l

= 35.5,

C a

= 40,

N i

= 59)

Q. How many grams of ammonia is obtained when 32.6 g of ammonium chloride reacts with calcium hydroxide during the laboratory preparation of ammonia?

[2 N H_{4} C l + C a (O H)_{2} \to C a C l_{2} + 2 H_{2} O + 2 N H_{3}]

[N=14, H=1, O=16, S=32, Cl=35.5]

Q. Ammonia reacts with sulphuric acid to give the fertilizer ammonium sulphate. Calculate the volume of ammonia [at STP] used to form

59 g

of ammonium sulphate.

[N = 14, H = 1, S = 32, O = 16]

The percentage of nitrogen by mass in ammonium sulphate is closest to (atomic masses H = 1, N = 14, O = 16, S = 32)

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Mole Concept

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