Ammonium chloride crystallises in a body centered cubic lattice with a unit distance of 386pm. Calculate the radius (in pm) of NH+4 ion. If the radius of Cl− ion is 181pm (Take√3=1.73)
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Solution
In a body- centered cubic lattice, oppositely charged ions touch each other along the cross- diagonal of the cube.
So, 2rc+2ra=√3a ⇒rc+ra=√32a =√32×386=333.89pm
Given that, ra=181pm ∴rc=(333.89−181.0)pm=152.89pm