wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

Ammonium chloride crystallises in a body-centred cubic lattice with a unit distance of 387 pm. Calculate (a) the distance between oppositely charged ions in the lattice and (b) the radius of the NH+4 ion if the radius of Cl ions is 181 pm.

Open in App
Solution

(a) In a body-centred cubic lattice, oppositely charged ions touch each other along the cross-diagonal of the cube.

So, 2rc+2ra=3a

or rc+ra=32a

=32×387=335.15 pm.

(b) Given that, ra=181 pm

rc=335.15181.0=154.15 pm

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Relation Between r and a
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon