Among $H_{2}$ , ${H e}_{2}^{+}$ , ${L i}_{2}$ , ${B e}_{2}$ , $B_{2}$ , $C_{2}$ , $N_{2}$ , $O_{2}^{-}$ , and $F_{2}$ , the number of diamagnetic species is
(Atomic numbers: $H = 1$ , $H e = 2$ , $L i = 3$ , $B e = 4$ , $B = 5$ , $C = 6$ , $N = 7$ , $O = 8$ , $F = 9$ )

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Solution

Six species are diamagentic as all electrons are paired. These are
$H_{2} (σ 1 s)^{2}$ ,
${L i}_{2} K K (σ 2 s)^{2}$ ,
${B e}_{2} K K (σ 2 s)^{2} (σ^{} 2 s)^{2}$ ,
$C_{2} K K (σ 2 s)^{2} (σ^{} 2 s)^{2} (π 2 p_{y})^{2} (π 2 p_{z})^{2}$ ,
$N_{2} K K (σ 2 s)^{2} (σ^{} 2 s)^{2} (π 2 p_{y})^{2} (π 2 p_{z})^{2} (σ 2 p x)^{2}$
$F_{2} K K (σ 2 s)^{2} (σ^{} 2 s)^{2} (σ 2 p x)^{2} (π 2 p_{y})^{2} (π 2 p_{z})^{2} (π^{} 2 p_{y})^{2} (π^{} 2 p_{z})^{2}$ .
Three species are paramgnetic as unpaired electrons are present.These are
${H e}_{2}^{+} (σ 1 s)^{2} (σ^{} 1 s)^{1}$
$B_{2} K K (σ 2 s)^{2} (σ^{} 2 s)^{2} (π 2 p_{y})^{1} (π 2 p_{z})^{1}$
$O_{2}^{-} K K (σ 2 s)^{2} (σ^{} 2 s)^{2} (σ 2 p x)^{2} (π 2 p_{y})^{2} (π 2 p_{z})^{2} (π^{} 2 p_{y})^{1} (π^{*} 2 p_{z})^{1}$ .

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Similar questions

H_{2}, H_{2}^{+}, L i_{2}, B e_{2}, B_{2}, C_{2}, O_{2}^{-},

N_{2}

F_{2}

H = 1, H e = 2, L i = 3, B e = 4, B = 5, C = 6, N = 7, O = 8, F = 9)

C_{2}, L i_{2}, O_{2}^{+}, H e_{2}^{+}

_{7}^{14} N +_{2}^{4} H e ⟶

_{8}^{17} O +_{1}^{1} H

_{4}^{9} B e +_{1}^{1} H ⟶

_{3}^{9} L i +_{2}^{4} H e

_{12}^{24} M g +_{2}^{4} H e ⟶

_{14}^{27} S i +_{0}^{1} n

_{5}^{10} B +_{2}^{4} H e ⟶

_{7}^{13} N +_{0}^{1} n

a, b, c, d, e, f, g, h

a^{2} + d^{2} + f^{2} + g^{2} = b^{2} + c^{2} + e^{2} + h^{2}

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