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Question

Among H2, He+2, Li2, Be2, B2, C2, N2, O2, and F2, the number of diamagnetic species is
(Atomic numbers: H=1, He=2, Li=3, Be=4, B=5, C=6, N=7, O=8, F=9)

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Solution

Six species are diamagentic as all electrons are paired. These are
H2(σ1s)2,
Li2KK(σ2s)2,
Be2KK(σ2s)2(σ2s)2,
C2KK(σ2s)2(σ2s)2(π2py)2(π2pz)2,
N2KK(σ2s)2(σ2s)2(π2py)2(π2pz)2(σ2px)2
F2KK(σ2s)2(σ2s)2(σ2px)2(π2py)2(π2pz)2(π2py)2(π2pz)2.
Three species are paramgnetic as unpaired electrons are present.These are
He+2(σ1s)2(σ1s)1
B2KK(σ2s)2(σ2s)2(π2py)1(π2pz)1
O2KK(σ2s)2(σ2s)2(σ2px)2(π2py)2(π2pz)2(π2py)1(π2pz)1.

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