Question

Among $LiCl,Be{Cl}_2,B{Cl}_3$ and $C{Cl}_4$ the covalent bond character follows the order:

• A. $LiCl>Be{Cl}_2>B{Cl}_3>C{Cl}_4$
• B. $LiCl<Be{Cl}_2<B{Cl}_3<C{Cl}_4$
• C. $LiCl>Be{Cl}_2>C{Cl}_4>B{Cl}_3$
• D. $LiCl<Be{Cl}_2<B{Cl}_3>C{Cl}_4$

Answer 1

The correct option is B $LiCl<Be{Cl}_2<B{Cl}_3<C{Cl}_4$

Greater is the electronegativity difference, greater is the ionic character. So when we move from $Li\to C$, electronegativity increases. So ,electronegativity difference is $LiCl>BeC{l}_2>BC{l}_3>CC{l}_4$ so $LiCl$ is having more ionic character. Thus $CC{l}_4$ is having more covalent character.