An 8000 kg engine pulls a train of 5 wagons, each of 2000 kg, along a horizontal track. If the engine exerts a force of 40000 N and the track offers a friction force of 5000 N, then calculate the net accelerating force and the acceleration of the train

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Solution

Net force exerted $= 40000 - 5000 N = 35000 N$

Total weight $= 8000 + (5 \times 2000) = 18000 k g$

$∴$ Acceleration $= \frac{35000}{18000} = 1.944 {m s}^{- 2}$

Hence, Net accelerating force $= 35000 N$ & acceleration $= 1.944 {m s}^{- 2}$ .

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Q. A

8000

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40000

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Q. A 8000 kg engine pulls a train of 5 wagons, each of 2000 kg, along a horizontal track. If the engine exerts a force of 40000 N and the track offers a friction force of 5000 N, then calculate:
(a) the net accelerating force;

A 8000 kg engine pulls a train of 5 wagons, each of 2000 kg, along a horizontal track. If the engine exerts a force of 40000 N and the track offers a friction force of 5000 N, then calculate:

(a) the net accelerating force and

(b) the acceleration of the train.

Q. 8000kg engine pulls a train of 5 wagons each of 2000 kg along a horizontal track. If engine exerts a force of 40000N and track offers friction of 5000N then calculate
1). Net accelerating force
2). Acceleration of train
3). Force of wagon 1 on wagon 2

Q. Question 7 (a)
A 8000 kg engine pulls a train of 5 wagons, each of 2000 kg, along a horizontal track. If the engine exerts a force of 40000 N and the track offers a friction force of 5000 N, then calculate:
(a) the net accelerating force;

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An 8000 kg engine pulls a train of 5 wagons, each of 2000 kg, along a horizontal track. If the engine exerts a force of 40000 N and the track offers a friction force of 5000 N, then calculate the net accelerating force and the acceleration of the train

Net force exerted =40000−5000N=35000NTotal weight =8000+(5×2000)=18000kg∴ Acceleration =3500018000=1.944ms−2Hence, Net accelerating force =35000N & acceleration =1.944ms−2.

Net force exerted $= 40000 - 5000 N = 35000 N$

Total weight $= 8000 + (5 \times 2000) = 18000 k g$

$∴$ Acceleration $= \frac{35000}{18000} = 1.944 {m s}^{- 2}$

Hence, Net accelerating force $= 35000 N$ & acceleration $= 1.944 {m s}^{- 2}$ .