An aeroplane is flying horizontally with a velocity of 600 km/h at a height of 1960 m. When it is vertically above a point A (point A on the ground), a bomb is released from it. The bomb strikes the ground at point B. The horizontal distance AB is
3.33 km
Horizontal displacement of the bomb
AB = Horizontal velocity × time available
AB = u × √2hg = 600× 518×√2×19609.8 = 3.33 km.