An air bubble in a glass sphere $(μ = 1.5)$ is situated at a distance 3 cm from a convex surface of diameter 10 cm. At what distance from the surface will the bubble appear ?

2.5 c m

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- 2.5 c m

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5 c m

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- 5 c m

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Solution

The correct option is B $- 2.5 c m$
Using the formula for refraction through curved surfaces, $\frac{N_{2}}{v} - \frac{N_{1}}{u} = \frac{N_{2} - N_{1}}{R}$

$\frac{1}{v} - \frac{1.5}{- 3} = \frac{1 - 1.5}{- 5}$

$\frac{1}{v} + 0.5 = 0.1$

$\frac{1}{v} = - 0.4$

$v = - \frac{10}{4} = - 2.5 c m$

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An air bubble in a glass sphere (μ=1.5) is situated at a distance 3 cm from a convex surface of diameter 10 cm. At what distance from the surface will the bubble appear ?

The correct option is B −2.5cmUsing the formula for refraction through curved surfaces, N2v−N1u=N2−N1R1v−1.5−3=1−1.5−51v+0.5=0.11v=−0.4v=−104=−2.5cm

An air bubble in a glass sphere $(μ = 1.5)$ is situated at a distance 3 cm from a convex surface of diameter 10 cm. At what distance from the surface will the bubble appear ?

The correct option is B $- 2.5 c m$
Using the formula for refraction through curved surfaces, $\frac{N_{2}}{v} - \frac{N_{1}}{u} = \frac{N_{2} - N_{1}}{R}$

$\frac{1}{v} - \frac{1.5}{- 3} = \frac{1 - 1.5}{- 5}$

$\frac{1}{v} + 0.5 = 0.1$

$\frac{1}{v} = - 0.4$

$v = - \frac{10}{4} = - 2.5 c m$