An air bubble in sphere of 4 cm diameter appears 1 cm from surface nearest to eye when looked along diameter. If reractive index of sphere is 1.5, calculate the distance of bubble from refracting surface.

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Solution

Given:
$v = - 1 c m$
$R = - 2 c m$

Using curved surface formula,
$\frac{μ_{2}}{v} - \frac{μ_{1}}{u} = \frac{μ_{2} - μ_{1}}{R}$
$\frac{1}{- 1} - \frac{1.5}{u} = \frac{1 - 1.5}{- 2}$

On solving further,
$u = - 1.2 c m$

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An air bubble in sphere of 4 cm diameter appears 1 cm from surface nearest to eye when looked along diameter. If reractive index of sphere is 1.5, calculate the distance of bubble from refracting surface.

Given: v=−1 cm R=−2 cm Using curved surface formula, μ2v−μ1u=μ2 −μ1R 1−1−1.5u=1−1.5−2 On solving further, u=−1.2 cm

Given:
$v = - 1 c m$
$R = - 2 c m$

Using curved surface formula,
$\frac{μ_{2}}{v} - \frac{μ_{1}}{u} = \frac{μ_{2} - μ_{1}}{R}$
$\frac{1}{- 1} - \frac{1.5}{u} = \frac{1 - 1.5}{- 2}$

On solving further,
$u = - 1.2 c m$