An alkane (molecular weight 72) forms only one monochlorinated product. Its formula is
A
(CH3)4C
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B
CH3(CH2)3CH3
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C
(CH3)2CHCH2CH3
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D
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Solution
The correct option is A(CH3)4C a) The alkane forms only one mono substituted product, it must have only one type of hydrogen atoms. there fore the alkane is 2, 2-dimethyl propane.