Question

An angle $y$ is ${14}^o$ greater than its complementary angle. The value of $y$ is:

• A. ${38}^o$
• B. ${52}^o$
• C. ${50}^o$
• D. ${104}^o$

Answer 1

The correct option is B ${52}^o$

The sum of two complementary angles is ${90}^o$. Thus, if one of the angles is $y$, the other angle will be ${90}^o-y$.

Given that $y$ is ${14}^o$ greater than its complementary angle, we have
$y=({90}^o-y)+{14}^o\Rightarrow 2y={104}^o\Rightarrow y={52}^o$