Question

An aqueous solution of glucose $\left(C_6{H}_{12}{O}_6\right)$ is labelled as $10\%\text{w/V}$. Calculate the volume in which $1$ mole of glucose will be dissolved.

• A. $1\text{L}$
• B. $3.6\text{L}$
• C. $1.8\text{L}$
• D. $0.9\text{L}$

Answer 1

The correct option is C $1.8\text{L}$

$1\text{g}$ mole is the mass of $1$ mole of substance in grams
Molecular mass of glucose:
$(12\times 6)+(12\times 1)+(16\times 6)=180\text{g mo}{l}^{-1}$
Hence mass of $1$ mole of glucose is $180\text{g}$
$10\%\text{w/V}$ means $10\text{g}$ of glucose is dissolved in $100\text{mL}$ of solution.
Then
$1\text{g}$ of glucose is dissolved in $\frac{100}{10}\text{mL}$
So, $180\text{g}$ of glucose will be dissolved in :
$=\frac{100}{10}\times 180=1800\text{mL}=1.8\text{L}$