An aqueous solution of glucose (C6H12O6) is labelled as 10%w/V. Calculate the volume in which 1 mole of glucose will be dissolved.
A
1L
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B
3.6L
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C
1.8L
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D
0.9L
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Solution
The correct option is C1.8L 1g mole is the mass of 1 mole of substance in grams
Molecular mass of glucose: (12×6)+(12×1)+(16×6)=180g mol−1
Hence mass of 1 mole of glucose is 180g 10%w/V means 10g of glucose is dissolved in 100mL of solution.
Then 1g of glucose is dissolved in 10010mL
So, 180g of glucose will be dissolved in : =10010×180=1800mL=1.8L