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Question

An aqueous solution of glucose (C6H12O6) is labelled as 10% w/V. Calculate the volume in which 1 mole of glucose will be dissolved.

A
1 L
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B
3.6 L
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C
1.8 L
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D
0.9 L
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Solution

The correct option is C 1.8 L
1 g mole is the mass of 1 mole of substance in grams
Molecular mass of glucose:
(12×6)+(12×1)+(16×6)=180 g mol1
Hence mass of 1 mole of glucose is 180 g
10% w/V means 10 g of glucose is dissolved in 100 mL of solution.
Then
1 g of glucose is dissolved in 10010 mL
So, 180 g of glucose will be dissolved in :
=10010×180=1800 mL=1.8 L

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