wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

An aqueous solution of glucose (C6H12O6) is labelled as 10% w/V. Calculate the volume in which 1 mole of glucose will be dissolved.

A
1 L
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3.6 L
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1.8 L
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
0.9 L
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 1.8 L
1 g mole is the mass of 1 mole of substance in grams
Molecular mass of glucose:
(12×6)+(12×1)+(16×6)=180 g mol1
Hence mass of 1 mole of glucose is 180 g
10% w/V means 10 g of glucose is dissolved in 100 mL of solution.
Then
1 g of glucose is dissolved in 10010 mL
So, 180 g of glucose will be dissolved in :
=10010×180=1800 mL=1.8 L

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon