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Question

An aqueous solution of glucose is 10% (w/V). The volume in which 1 mole of glucose is dissolved, will be:

A
18 L
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B
9 L
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C
0.9 L
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D
1.8 L
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Solution

The correct option is D 1.8 L
10 g glucose is present in 100 mL solution.
Moles of glucose =10180=118
Molarity=MolesofsoluteVolume(Litres)=118×0.1=59 M
Let the volume required for 1 mole glucose solution be V
59×V=1
V=95 Litres=1.8 Litres

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