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Question

An aqueous solution of X is is added slowly to an aqueous solution of Y as shown in Column I. The variation in conductivity of these reactions is given in Column II. Match Column I with Column II and select the correct answer using the codes given below the Columns.
Column IColumn IIP.(C2H5)3XN+CH3COOHY1.Conductivity decreases and then increasesQ.KI(0.1M)X+AgNO3Y(0.01M)2.Conductivity decreases and then does not change muchR.CH3COOHX+KOHY3.Conductivity increases and then does not change muchS.NaOHX + HIY4.Conductivity does not change much and then increases

A
P - (3) Q - (4) R - (2) S - (1)
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B
P - (4) Q - (3) R - (2) S - (1)
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C
P - (2) Q - (3) R - (4) S - (1)
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D
P - (1) Q - (4) R - (3) S - (2)
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Solution

The correct option is A P - (3) Q - (4) R - (2) S - (1)
(P) X(C2H5)3N+YCH3COOHCH3COO(aq)+(C2H5)3NH+(aq)
As CH3COOH is a weak acid, its conductivity is already less. On addition of weak base, acid - base reaction takes place and new ions are created.
So conductivity increases.
(Q) KI(0.1 M)+AgNO3(0.01 M)AgI(ppt)+KNO3(aq).
As the only reaction taking place is precipitation of AgI and in place of Ag+,K+ is coming in the solution, conductivity remain nearly constant and then increases.
(R) CH3COOH+KOHCH3COOK(aq)+H2O
OH+(aq) is getting replaced by CH3COO, which has poor conductivity. So conductivity decreases and then after the end point, due to common ion effect, no further creation of ions take place. So, conductivity remain nearly same.
(S) NaOH+HINaI(aq)+H2O
As H+ is getting replaced by Na+ conductivity decreases and after end point. due to OH, it increases.
So answer is: (P)- (3); (Q) - (4); (R) - (2); (S) - (1).

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