An aromatic compound of molecular formula $C_{6} H_{4} B r_{2}$ was nitrated then only one product of formula $C_{6} H_{3} B r_{2} N O_{2}$ was obtained. The original compound is:

o-dibromobenzene

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m-dibromobenzene

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p-dibromobenzene

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Both A&C

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Solution

The correct option is B p-dibromobenzene
Since only one product is obtained, all the four aromatic hydrogen atoms are equivalent. This is possible only if the substituents are in para position.
Thus the original compound is p-dibromobenzene.

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