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Standard X
Physics
Velocity Ratio
an effort of ...
Question
an effort of 6Kgf is applied on a machine through displacement of 90 cm,when a load of 100 kgf moves through a distance of 4 cm,Calculate i)velocity ratio ii)M.A iii)%of efficiency machine
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Solution
V
e
l
o
c
i
t
y
r
a
t
i
o
=
d
i
s
p
l
a
c
e
m
e
n
t
b
y
t
h
e
e
f
f
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t
d
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p
l
a
c
e
m
e
n
t
b
y
t
h
e
l
o
a
d
=
90
c
m
4
c
m
=
22
.
5
.
M
e
c
h
a
n
i
c
a
l
a
d
v
a
n
t
a
g
e
M
A
=
L
o
a
d
E
f
f
o
r
t
=
100
K
g
f
6
K
g
f
=
16
.
67
.
E
f
f
i
c
i
e
n
c
y
=
M
A
V
e
l
o
c
i
t
y
r
a
t
i
o
=
100
6
÷
90
4
=
100
6
×
4
90
=
40
54
=
20
27
.
E
f
f
i
c
i
e
n
c
y
%
=
20
27
×
100
=
74
.
7
%
.
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