1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# An electric discharge is passed through a mixture containing 50 c.c. of O2 and 50 c.c. of H2. The volume of the gases formed (i) at room temperature and (ii) at 1100C will be

A
(i) 25 c.c. (ii) 50 c.c.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
(i) 50 c.c. (ii) 75 c.c.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(i) 25 c.c. (ii) 75 c.c.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
(i) 75 c.c. (ii) 75 c.c.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is C (i) 25 c.c. (ii) 75 c.c.At room temperature 2H2(g)+O2(g)→2H2Olt=050ml50ml0t=t50−2x50−x2x=025 gases (50) liquid In this case H2 is limiting reagent x=25 ml At 110∘C 2H2(g)+O2(g)→2H2O(g)Vgas=75 mlt=t025ml2×50ml

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
CHEMISTRY
Watch in App
Join BYJU'S Learning Program