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Question

# An electric discharge is passes through a mixture containing 50 c.c. of H2 and 50 c.c. of O2. The volume of the gases formed (i) at room temperature and (ii) at 110∘C will be:

A

(i) 25 c.c. (ii) 50 c.c

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B

(i) 50 c.c. (ii) 75 c.c

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C

(i) 25 c.c. (ii) 75 c.c

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D

(i) 75 c.c. (ii) 75 c.c

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Solution

## The correct option is C (i) 25 c.c. (ii) 75 c.c 2H2 + O2 → 2H2O 2H2(g) + O2(g) → 2H2O(l) at room temp 2H2(g) + O2(g) → 2H2O(g) at 110∘C At room temperature 25mL of O2 gas would be left unreacted while at 110∘C 50mL ofH2O and 25mL ofO2 will be present.

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