An electric discharge is passed through a mixture contaning $50$ cc of $O_{2}$ and $50$ cc of $H_{2}$ . The volume of the gases formed (i) at room temperature and (ii) at $110^{0} C$ will be, respectively:

(i)

25

cc (ii)

50

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(i)

50

cc (ii)

75

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(i)

25

cc (ii)

75

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(i)

75

cc (ii)

75

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Solution

The correct option is D (i) $25$ cc (ii) $75$ cc
At room temperature, $50$ cc of hydrogen will react with $25$ cc of oxygen to obtain liquid water.
Thus, $25$ cc of oxygen will be left behind.
At $110^{0} C$ , $50$ cc of hydrogen will react with $25$ cc of oxygen to obtain $50$ cc of water vapor.
Hence, the total volume of gas will be $75$ cc.

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