The correct option is B Rs. 324
Given:
Resistance, R=8 Ω
Current drawn, i=15 A
Time duration, =2 h per day.
Cost of operating, Rs. 3 per kWh
The energy E consumed by the heater in 1 day would be:
E=i2Rt=152×8×2
or E=3600 Wh=3.6 kWh
The total energy H consumed by the heater in 30 days would be:
H=3.6×30 kWh=108 kWh
Cost of operating at the rate of Rs. 3/kWh=3×108
⟹ Rs. 324/−