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Question

An electric refrigerator rated 400 W operates for 8 hours a day. What is cost of energy to operate it for 30 days at Rs 3.00 per KWh?

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Solution

Dear Student ,
Here in this question the consumption of power = 400 W = 0·4 KW
Time = 8 hrs/day
No. of days = 30 days
Therefore , total time = t = 30× 8 =240 hrs
Energy = Power × time = 0·4×240= 96 KWh
Therefore if cost of energy is Rs 3 per KWh then the total cost of energy for 30 days = 96×3=288 Rs
Regards

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