An electric refrigerator rated 500W operates 24 hours/day. What is the cost of the energy to operate it for 20 days at rupees 2.00 per kWh.

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Solution

Given,

Power = P = 500W = 500/1000 kW = 0.5 kW

Total time for which the refrigerator operated = t = 24 hours x 20 days = 480 h

Since, Energy consumed = P x t E = 0.5x 480 kWh = 240 kWh

Therefore, total cost required to operate the refrigerator for the month = 240 x 2 = 480 INR.

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